Bubble Sort on Python3

Question

Bubble Sort on Python3

def bubble_sort(list):
for i in range(len(list)):
    for j in range(len(list)-1):
        if list[j] > list[j+1]:
                list[j], list[j+1] = list[j+1], list[j]
        else:
            continue

I just made this bubble sort , but I ended up realizing that it makes some unnecessary interactions on account of for greater (I), I would like to know how to stop all interactions when the list is sorted / know when the list will be sorted

0

python python-3.x algoritmo classificação

Author: Angelo Gonçalves Salles, 2018-07-04

Source

1 answers

score 3 · Accepted Answer

How about using a control flag to determine if the list has been sorted completely:

def bubble_sort( lst ):
    ok = False
    while not ok:
        ok = True
        for i in range(len(lst)-1):
            if lst[i] > lst[i + 1]:
                lst[i], lst[i + 1] = lst[i + 1], lst[i]
                ok = False
    return lst

print(bubble_sort([7,6,5,4,9,1,6,2,4,9,0,3]))

Output:

[0, 1, 2, 3, 4, 4, 5, 6, 6, 7, 9, 9]

In Python, all this is already ready, and in the practical world, there is no need for such an implementation.

All this paraphernalia can be replaced simply by:

lst = [7,6,5,4,9,1,6,2,4,9,0,3]
print(sorted(lst))

Output:

[0, 1, 2, 3, 4, 4, 5, 6, 6, 7, 9, 9]