Copy files in batch, renaming them with the name of the original directory

Assuming the names are random, both of the folders and the files, what will suffice will be a recursive function to take the photos, use the cp and copy to a new destination, something like

• /home/docs/pasta/foo.jpg ➡️ /home/target/pasta_foo.jpg

The" function " inside the bash could be something like move_recursive, so with the command cp will move the file to the desired destination (you can exchange for mv if you want to move for good, which I do not recommend since the script was not 100% tested), so this:

echo "cp \"$file\" \"${destination_path}${only_dirname}_${only_filename}\""

Should be this:

cp "$file" "${destination_path}${only_dirname}_${only_filename}"

Or this:

mv "$file" "${destination_path}${only_dirname}_${only_filename}"

Note that I used ${...} to be able to work with underline, because if I did this $only_dirname_$only_filename would fail.

I put in a echo the command cp to avoid executing without being sure that it worked, look at the result of all command and will know if it is executing correctly

To pick up only the name of the file or folder I used:

$(basename $current_path)

Or script all it should look like this:

#!/bin/bash

# "função" para recursividade
move_recursive() {
    echo ""
    echo "-------------------------"
    echo "Lendo pasta: $path"
    echo "-------------------------"

    current_path="$1"

    for file in "$1"/*
    do
        if [ -d "$file" ]
        then
            move_recursive "$file"
        elif [ -f "$file" ]
        then
            only_dirname=$(basename $current_path)
            only_filename=$(basename "$file")

            # tire do echo para executar
            echo "cp \"$file\" \"${destination_path}${only_dirname}_${only_filename}\""
        fi
    done
}

# pasta de destino (troque pela pasta de destino, caminho completo)
destination_path="/home/destination/"

# pasta aonde estão as fotos (troque pelo caminho completo desejado)
source_path="/home/bar/"

move_recursive $source_path

Swapping whitespace for underline / underscore with bash

I couldn't test because my system isn't unix-like, so I can't state if it works, but I believe if to use it this way:

echo "cp \"$file\" \"${destination_path}${only_dirname//[[:blank:]]/_}_${only_filename//[[:blank:]]/_}\""

All spaces will be exchanged for _, in a practical example, this would be:

#!/bin/bash

foo="a b c d"

echo ${foo//[[:blank:]]/_}

Being [[:blank:]] the regular expression for whitespace (TABs too) and after the / would be the character that will replace.