Counter and for and while loops (Python) need to write a counter

Question

Counter and for and while loops (Python) need to write a counter

I can't figure it out, I need to write a program to attach an image I can't, I'll write it like this:

Enter n calculate:

s=1/3^2+1/5^2+1/7^2+...+1/(2n+1)^2

Using the for and while{[5 loops]}

What am I doing wrong?

n=int(input("Введите n: "))
i=3
y=1
z = input("Выберите способ 1 - цикл while, 2 - цикл for: ")

if z == "1":
    while i<2*n+1:
        s=y/(round(i, 2*n+1))**2
        print("S=", s)
        i+=2
        s=y/(round(i, 2*n+1))**2
        print("S=", s)
        break
else:
    print("")

P.S. I didn't write the second part with the "for" operator

2

while операторы python-3.5

Author: Apo-S, 2016-11-17

Source

1 answers

score 1 · Answer 1

n = 5
s = 0.0
for x in range(1, n + 1):
    s += 1 / (2 * x + 1) ** 2
print('{0:.3f}'.format(s))

x = 1
s = 0.0
while x <= n:
    s += 1 / (2 * x + 1) ** 2
    x += 1
print('{0:.3f}'.format(s))

# 0.192
# 0.192