How in Python to determine which random number will most often appear from the list of values starting from (00, 0,1,2 ... 36?

Question

How in Python to determine which random number will most often appear from the list of values starting from (00, 0,1,2 ... 36?

I recently started learning the random module. You need to do it 1000 times and identify the most frequent number, if possible in % relation, or at least how many times.

If you can still output not 1, but 5 of the most frequent numbers.

The problem with 00, I do not understand how to write it as a number.

0

python python-3.x numpy случайные-числа

Author: Kromster, 2020-03-12

Source

2 answers

score 1 · Answer 1

import random
from collections import Counter

MAX_NUM = 36        # 0, 1, ..., 36        (00 то же самое как 0)
RAND_NUMS = 1000    # сколько случайных
OUTPUT_NUMS = 3     # сколько нужно вывести

random_list = random.choices(range(MAX_NUM+1), k=RAND_NUMS)

print(Counter(random_list).most_common(OUTPUT_NUMS))

(00 same as 0.)

Test for MAX_NUM = 4, RAND_NUMS = 10 and OUTPUT_NUMS = 3:

In[217]: random_list = random.choices(range(MAX_NUM+1), k=RAND_NUMS)
In[218]: random_list

[3, 4, 2, 3, 1, 2, 2, 1, 3, 3]

In[219]: Counter(random_list).most_common(OUTPUT_NUMS)

[(3, 4), (2, 3), (1, 2)]

B %:

most_common = Counter(random_list).most_common(OUTPUT_NUMS)
most_common_perc = [(i, 100 * j / RAND_NUMS) for i, j in most_common]
print(most_common_perc)

[(3, 40.0), (2, 30.0), (1, 20.0)]

score 1 · Answer 2

If I understood correctly, then so somehow:

from random import choice
from collections import Counter

if __name__ == '__main__':
    rnd = [
        '00',
        '0',
        '1',
        '2',
# ...
        '31',
        '32',
        '33',
        '34',
        '35',
        '36'
    ]

    rnd_list = [choice(rnd) for _ in range(1000)]

    d = Counter(rnd_list)
    print(d.most_common(5))
    print({a[0]: f'{a[1] / 1000 * 100:.1f}%' for a in d.most_common(5)})