How random is random.randint in python?

Question

How random is random.randint in python?

import random
x=0
for i in range(10000):
    my_series = [random.randint(0, 11) for i in range(100)]
    x += 1 if len(list(filter(lambda x: x % 2 == 1, my_series))) < len(list(filter(lambda x: x % 2 == 0, my_series))) else -1
    print(x)

Why is the preponderance always in the negative even though the list generation is random and the possible number of even and odd values is the same(from 0 to 11).

0

python случайные-числа

Author: Michael Larshin, 2019-11-30

Source

1 answers

score 4 · Accepted Answer

Because the cases where even and odd are the same are considered in -1.

If the list my_series is made of odd length, then х will fluctuate around 0 (although there may be quite significant deviations).