How to get Gmail source code using Python3

I am accessing the Email using this code q I found and adapted:

import requests
from bs4 import BeautifulSoup

form_data = {'Email': '[email protected]', 'Passwd': 'senhaexemplo'}
post = "https://accounts.google.com/signin/challenge/sl/password"

def login(self):
    with requests.Session() as s:
        soup = BeautifulSoup(s.get("https://mail.google.com").text, "html.parser")
        for inp in soup.select("#gaia_loginform input[name]"):
            if inp["name"] not in form_data:
                form_data[inp["name"]] = inp["value"]
        s.post(post, form_data)
        html = s.get("https://mail.google.com/mail/u/0/#inbox").text
        print(html)

My goal is to take the Emails and print on the screen, with subject and content, and I know how to do that using certain html tags... But for this I need the source code of the site, and when I'm going to look at the result of print(html) does not come with any tag, everything is compressed... Something like this:

{\"1\":\"be_35\",\"53908043\":0},{\"1\":\"be_36\",\"53908043\":0},{\"1\":\"be_30\",\"53908043\":0},{\"1\":\"be_31\",\"53908043\":0},{\"1\":\"be_169\",\"53908043\":0},{\"1\":\"su_ltz\"},{\"1\":\"ic_sspvcd\"},{\"1\":\"bu_wdtfsm\"},{\"1\":\"be_26\",\"53908043\":0},{\"1\":\"be_29\",\"53908043\":0},{\"1\":\"be_280\",\"53908043\":0},{\"1\":\"be_281\",\"53908043\":0},{\"1\":\"30\",\"53908046\":0},{\"1\":\"31\",\"53908043\":0},{\"1\":\"32\",\"53908046\":0},{\"1\":\"33\",\"53908046\":0},{\"1\":\"be_277\",\"53908043\":0},{\"1\":\"34\",\"53908045\":\"\"},{\"1\":\"be_278\",\"53908043\":0},{\"1\":\"35\",\"53908046\":0},{\"1\":\"be_275\",\"53908043\":0},{\"1\":\"be_276\",\"53908043\":0},{\"1\":\"be_273\",\"53908043\":1},{\"1\":\"38\",\"83947487\":{}},{\"1\":\"se_192\",\"53908045\":\"en,es,pt,ja,fr\"},{\"1\":\"be_274\",\"53908043\":0},{\"1\":\"39\",\"53908046\":0}

How can I get the correct source code?