How to make a logged in user helper Asp.NET MVC 4?

I need to implement a logged-in user Helper, i.e. a static class that returns information about the logged-in user of context. The idea is to use the information in both Controllers and Views.

Author: Leonel Sanches da Silva, 2014-05-21
Source

2 answers

@ LuizNegrini you can try using a singleton in the ProfessionalUser class. By adding a static property of the same type as the class, when called you can fetch the current user through another external method and using the encrypted user id in a cookie or session as a parameter.

namespace Aplicacao.Model
{
    public class ProfessionalUser
    {
        private static ProfessionalUser _user;
        private static string _keyUser = "idUserOuQualquerChaveQueVoceEscolher";

        public int IdProfessionalUser { get; set; }

        public string Email { get; set; }

        public string ReEmail { get; set; }

        public string Password { get; set; }

        public string RePassword { get; set; }

        public string Name { get; set; }

        public int IdProfessionalRegister { get; set; }

        public string City { get; set; }

        public string State { get; set; }

        public int Phone { get; set; }

        public static ProfessionalUser UsuarioAtual
        {
            get
            {
                if(_user == null)
                {
                    int idUser = 0;
                    HttpCookie cookie = HttpContext.current.Request.Cookies[_keyUser];
                    string v = cookie != null ? cookie.Value : String.Empty;
                    int.TryParse(v, out idUser);
                    _user = (new QualquerGerenciadorDeUsuario()).FuncaoQuePegaOUsuarioPeloID(idUser);
                }
                return _user;
            }
            set
            {
                int idUser = 0;
                if(value != null && value.ID > 0)
                {
                    idUser = value.ID;
                    _user = value;
                }else
                    _user = null;

                HttpCookie cookie = new HttpCookie(_keyUser, idUser.ToString());
                HttpContext cxt = HttpContext.current;
                cookie.Expires = DateTime.Today.AddHours(3);// o cookie vale por 3 horas
                cxt.Response.Cookies.Add(cookie);
            }
        }
    }
}

Already in View, you can call the property at any time in two ways: 

@Aplicacao.Model.ProfessionalUser.UsuarioAtual

And from there you can take any and all user property current:

@Aplicacao.Model.ProfessionalUser.Current user.IdProfessionalUser

The other way is by including namespace in View: 

@using Aplicacao.Model
@ProfessionalUser.UsuarioAtual

... and the properties is the same: 

@ProfessionalUser.UsuarioAtual.IdProfessional

I hope it helped.

Att, Uilque Messiah

 4
Author: Uilque Messias, 2014-05-22 21:46:34

Follows a Helper I did to get logged in user information.

This project uses Membership, that is, it is an old approach, but it serves as an example for improvements in the case of ASP.NET Identity: 

public static class LoggedUserHelper
{
    private static MyProjectContext context = new MyProjectContext();

    public static UserProfile CurrentUserInfo(IPrincipal User) {
        int currentUserId = WebSecurity.GetUserId(User.Identity.Name);
        return context.UserProfile.AsNoTracking().SingleOrDefault(x => x.UserId == currentUserId);
    }

    public static int UserId(IPrincipal User) {
        return WebSecurity.GetUserId(User.Identity.Name);
    }

    public static int UserId(String UserName) {
        return WebSecurity.GetUserId(UserName);
    }

    ...
}

Obviously my model UserProfile has several additional columns, but I will put only the minimum necessary to work: 

public class UserProfile {
    [Key]
    public int UserId { get; set; }

    ...
}
 2
Author: Leonel Sanches da Silva, 2014-05-21 22:58:08