Lua comparison,numbers and keys tables

The file contains integers in decimal form. Convert each a number in binary form. Perform data encryption so that every eight binary characters turn into a letter of the Latin alphabet. The table of correspondence of codes to letters is contained in the second the file. Provide a function for performing decryption.

function tobin(num)
        local tmp = {}
        repeat
            tmp[#tmp+1]=num%2
            num = math.floor(num/2)
        until num==0 
        return table.concat(tmp):reverse()
    end

    local function main()
     io.input("number.txt")
     local m = {}
      for i = 1, 6 do
        local val = io.read("*number")
          if val == nil then break end
            m[i] = tobin(val)
        print(m[i])end


     local a = {} 
     --local n = 1 
    io.input("shfr.txt") 
    while true do
      local line = io.read("*line") 
      if line == nil then break end 
      x,y = string.match(line,"([01]+) (%a)") 

      a[x] = y 
    end

    for k,v in pairs(a) do
      print("["..k.."]="..v)
    end

      for i = 1, 6 do
     if a[m[i]]  then m[i] = y end
     print(m[i])
      end


    io.close()
    end
    main()

Here I tried to compare binary numbers with a key and replace them with a letter that is in the value the key. but it only outputs F F F F F

 for i = 1, 6 do
         if a[m[i]]  then m[i] = y end
         print(m[i])
          end

This is the table 

[11001001]=F
[11001100]=D
[11001110]=A
[11110101]=C
[11111110]=E
[11010111]=B


 а это m[i]
11001110
11010111
11110101
11001100
11111110
11001001
 0
lua
Author: P.L, 2016-09-08
Source

2 answers

if a[m[i]] then m[i] = y end

And what is the global variable y?

There's the last value from the read loop shfr.txt. Replace with a[m[i]]

 0
Author: FareakyGnome, 2016-09-08 22:05:47

With the table proposed in this question, formatted in the same way as in your previous question, and with the input data voiced in this question, here is a simple code:

local a={}

for line in io.lines("таблица") do
  local x,y=string.match(line,"([01]+) (%a)")
  a[x]=y
end

for line in io.lines("входные.данные") do
  print(a[line])
end

Will output what you probably expect:

A
B
C
D
E
F

Free recommendation: if you need to write a program in some programming language, and you do not want to learn even the basics of this language, then it is faster and easier not to ask to write you a program in pieces (once and twice), and then it is not very meaningful to try to put these pieces together, but immediately turn to some freelance exchange. good luck!

 -1
Author: aleksandr barakin, 2017-04-13 12:53:29