Mathematica integrals

How to choose a replacement that leads the integral of a given function to the integral of a rational function and decompose it into simple fractions by the method of indefinite coefficients using wolfram mathematica?

Author: Olegfer, 2016-06-20

1 answers

You can try this:

f[x_]=... - изначальная функция

F[x_] = FunctionInterpolation[f[x],{x, x0, x1}]

Integrate[F[x],x]
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Author: Theta, 2017-03-21 04:46:20