Output date() in php with an arbitrary offset

Question

Tell me how to output as short as possible in php

echo (date("d M Y в H:i"));

With a random offset in minutes from the current time, for example, take away 34 minutes?

1

php дата

Author: Viktor, 2016-05-21

Source

2 answers

score 2 · Answer 1

Time

$time = time() - 34 * 60; // секунды
echo date('d M Y в H:i', $time);

Strtotime

$time = strtotime('-34 minutes');
echo date('d M Y в H:i', $time);

DateTime

$date = new \DateTime('-34 minutes');
echo $date->format('d M Y в H:i');

score 0 · Answer 2

echo (date("d M Y в H:i", time()-34));

0

Author: Viktor, 2016-05-21 14:29:18