arredondamento

How to use python round

When I use python's round it converts 1.5 to stop 2, but with 2.5 it leaves 2. How do I make it round 2.5 to 3 ? Being that any other number that does not contain the number 2 it rounds right

How do I arredondo the third decimal place in php?

I need a help, I have following problem, I need to round the third decimal place up, how do I do it? EX: From 3.49 convert ... From 3.43 converts to 3.50 From 3.42 converts to 3.50 When I use function round it converts to 4.00 Can anyone help me?

Rounding numbers in C# being the decimal place 0 or 5

I need to subtract numbers such that they have only one decimal place worth 0 or 5. For example 1 -> 1 1.1 -> 1.5 1.4 -> 1.5 1.5 -> 1.5 1.6 -> 2 2 -> 2 Does anyone know a simple way to do this?

C# - 5 significant numbers with at least 2 decimal places

Guys, does anyone know a way that I can transform a number with at least 5 Significant Digits and added to this factor, must ... .Length + pad0, '0'); } numero = string.Join(",", parts); } return numero; }

Rounding in SQL

I need to perform a rounding of a result. In Oracle it looks like this: SALDO_TONELADA = (A.PESO * 20,0); The value of co ... r, but I need the result to be with 2 or 3 characters to correct the calculation of other columns that depend on this result.

Sum of two floats with 2 decimal places resulting in 4 decimal places in JAVA

I am having a problem in JAVA where I want to store calculation results with only 2 decimal places in SQL Server. For this at ... s): INSERT INTO tableX (valor) values (ROUND(?,2)) But continues to result in a number of 4 decimal places after the sum.

Sinking up

I have this values, where contrato.Count = 63 and 63/50 = 1.26. I would like it to yield to 2, I am doing this way: decimal arrendondamento = contrato.Count / 50; var valorArredondado = Math.Ceiling(arrendondamento); But it always brings me 1.

Decimal rounding following abnt 5891 [closed]

closed . This question needs to be more objective and is not currently accepting answers. ... l [0.35, 0.35, 0.35, 0.35, 0.34, 0.34, 0.34, 0.34, 0.31, 0.32] What would be the best way to adapt these rules in JavaScript?