nan
How to fill in NaN if one value is possible?
Let's imagine a table of two columns in a dataframe:
0 NaN
0 NaN
0 1
1 0
1 5
1 NaN
2 0
0 NaN
0 1
2 1
2 NaN
3 NaN
3 500
3 N ... y the only non - NaN value on the right?
Desired result:
0 1
0 1
0 1
1 0
1 5
1 NaN
2 0
0 1
0 1
2 1
2 NaN
3 500
3 500
3 500
Replacing values with NaN
I work with a table of data that has both positive and negative values.
How can I replace all positive values in a certain column with NaN?
I tried it like this:
df.loc[df['days_employed'] > 0, 'days_employed'] = "NaN"
But I got an error.
Outputs in the compiler instead of the number nan
Created a list of numbers 3 5 1 9
struct Data
{ int a;
};
struct List
{ Data d;
List *next;
};
... >d.a;
++count;
}
cout << "Average = " << double(sum)/count << endl;
return 0;
}
Why?
Why is the constant NAN evaluated as true when testing it with is numeric?
I was doing a test with the constant NAN in PHP, since until then I had never used the same. I ran tests out of curiosity.
I ... ssion, two other tests revealed contradictory results:
is_float(NAN) // true
filter_var(NAN, FILTER_VALIDATE_FLOAT)// false
What does Nan mean in javascript?
When we have an error in the sum of a number with JavaScript, it is returned NaN.
Example:
parseInt('a') + 3; //NaN
What Does NaN mean?