How to create an array of function pointers in C / C++

Question

How to create an array of function pointers in C / C++

4

c++

Author: Nicolas Chabanovsky, 2010-10-20

Source

3 answers

void (*pfn_MyFuncType[10])(char * str, int len);

Or

void (**pfn_MyFuncType)(char * str, int len);

9

Author: Hedgehog, 2011-01-13 11:36:38

In the style of c++11

#include <vector>
#include <iostream>
#include <functional>


void foo(int i) {
    std::cout << i << '\n';
}


int main() {
    std::vector<std::function<void(int)>> vfunc;
    vfunc.push_back(foo);
    vfunc[0](1);
    return 0;
}

0

Author: Andrio Skur, 2019-03-19 13:08:02

score 5 · Accepted Answer

You must declare a new type-a pointer to a function. This is done by simply declaring a pointer to a function. Next, you need to declare an array of the function pointer type. For example:

typedef void (*pfn_MyFuncType)(char * str, int len);
pfn_MyFuncType * myFuncTypeArray;
// или
pfn_MyFuncType myFuncTypeArray[10];