jQuery.each()
I bypass the elements in this way:
jQuery.each($('#content_wrap > .an_post'), function() {
setTimeout(function(){console.log('Hello timeout');}, 10000);
});
For example
$('#content_wrap > .an_post').size()
Is equal to 4. Then in theory .each will bypass 4 elements in 40 seconds, but it is triggered after 10 and outputs 4 'Hello timeout' to the console at once. Why is this happening? This plunges me into the depths of despair!
In general, I wanted to do something like this:
jQuery.each($('#content_wrap > .an_post'), function() {
$(this).fadeIn(1500);
});
That is, so that 4 elements disappear one after the other with a difference in animation of about a second.
2 answers
In theory .each will bypass 4 elements in 40 seconds, but it is triggered after 10 and outputs 4 'Hello timeout' to the console at once. Why is this happening?
As you know, setTimeout calls the function passed as a parameter after a certain period of time from the moment of calling setTimeout itself, and since in the loop 4 elements are sorted sooooo fast, the difference between calls is equal to milliseconds, which do not affect the overall picture
To make 4 elements one after the other they disappeared with a difference in animation of about a second
$('#content_wrap > .an_post').each(function(idx){
$(this).delay(1000*idx).fadeOut(1500);
});
I wrote it on my knee. The meaning, I think you will understand)
jQuery.each($('#content_wrap > .an_post'), function(id) {
$(this).delay(1000*id).fadeOut(1500);
});