XML parsing in Android

Question

XML parsing in Android

Please tell me, I need to parse a simple XML'ku vida:

<?xml version="1.0" encoding="UTF-8"?>
<result>
  <status code="200" />
   <building number="434" part="0" url="http://www.piccadillyrecords.com/mp3/Sum%2041%20-%20No%20Brains.mp3">Gu</building>
 </result>

Can you tell me how to make it easier? Mb is there some simple class for parisng? Somewhere I saw an analog of php'shnoy simplexml, but now I can't find it

4

android sax dom

Author: JIesnik, 2012-04-23

Source

4 answers

score 3 · Answer 1

I would write a simple parser based on SAX like this (written on my knees, so please do not throw tomatoes!)

factory = XmlPullParserFactory.newInstance();
factory.setNamespaceAware(false);
xpp = factory.newPullParser();
StringReader sw=new StringReader(s); //s содержит ваш XML
xpp.setInput(sw); //подаем на вход парсера
int eventType = xpp.getEventType();
while (eventType != XmlPullParser.END_DOCUMENT)
{
    if (eventType == XmlPullParser.START_TAG) //начальный тег
    {
        inBuilding=false;
        if(xpp.getName().compareTo("status")==0)
            code = xpp.getAttributeValue(null, "code"); //читаем атрибут code
        else if(xpp.getName().compareTo("building")==0)
        {
            number = xpp.getAttributeValue(null, "number");
            part = xpp.getAttributeValue(null, "part");
            url = xpp.getAttributeValue(null, "url");
            inBuilding=true;
        }
    }
    else if(eventType==XmlPullParser.TEXT)
    {
        if(inBuilding) //если мы внутри тега building
            buildingValue=xpp.getText();
    }
    eventType=xpp.next();
}

Naturally, the values of attributes, fields, and so on. after reading it, you need to put it somewhere. Well, you're already there yourself. :)

score 0 · Answer 2

Java has a lot of tools for working with XML.

Example of deserialization using Simple

Serializer s = new Persister();
Example e = s.read(Example.class, new File("example.xml"));

score 0 · Answer 3

XmlPullParser

XML Pull Parser is an interface that defines parsing functionality...

0

Author: Gorets, 2012-04-23 17:43:24

score 0 · Answer 4

Read it here: http://www.ibm.com/developerworks/opensource/library/x-android/

Another option:

//вспомогательный метод - получает содержимое тэга
String getTagValue(String sTag, Element eElement) { 
    NodeList nlList = eElement.getElementsByTagName(sTag).item(0).getChildNodes();
    Node nValue = (Node) nlList.item(0);

    return nValue.getNodeValue();
}

void test() {
   File xmlFile = new File(PathToFile);

   DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
   DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();

   Document doc = dBuilder.parse(fXmlFile);
   doc.getDocumentElement().normalize();

   doc.getDocumentElement().getNodeName(); //имя корневого тэга
   NodeList nList = doc.getElementsByTagName("building"); //получаем все теги building
   for (int nodeIndex = 0; nodeIndex < nList.getLength(); temp++) { //пробегаем тэги
       Node nNode = nList.item(temp);
       if (nNode.getNodeType() == Node.ELEMENT_NODE) {
           Element eElement = (Element) nNode;
           getTagValue("building", eElement); //получить содержимое текущего тэга
           eElement.getAttribute("number"); //получить значение аттрибута
       }
   }
}